tolong kk untuk hari ini dikunpulkan pliss dijawab
Jawaban:
D. 10,0 gram
Penjelasan:
Mr.CaCO3 = 40 + 12 + 3×16 = 40 + 12 + 48 = 100
m.Ca = jmlh atom × Ar / Mr × m.CaCO3
m.Ca = 1×40gr/mol/100gr/mol × 25gr
m.Ca = 40/100 × 25gr
m.Ca = 40/4gr
m.Ca = 10,0gr
[answer.2.content]
